Given the following program, what is the output? It must be in the correct order

Question

Given the following program, what is the output? It must be in the correct order! Figure it out by hand rather than by coding it!

public class Scope {

    int x = 1;  
    static int y = 2;

    public Scope() {
        int x = 5;

        System.out.println("x in Scope(1): " + x);

        a();
        b();
        a();
        b();

        System.out.println("x in Scope(2): " + x);
    }

    void a() {
        int x = 25;
        System.out.println("x in a(1): " + x);

        ++x;
        System.out.println("x in a(2): " + x);
    }

    void b() {
        System.out.println("x in b(1): " + x);

        x *= 10;
        System.out.println("x in b(2) " + x);
    }

    public static void main(String[] args) {
        Scope s = new Scope();

        System.out.println("y in main(1) " + y);   

        System.out.println("y in main(2) " + s.y);    }
}

------------------------ OUTPUT --------------------------------

Explanation / Answer

x in Scope(1): 5     //constructor of the scope is called
x in a(1): 25       // inside a() method ,local variable got the highest priority so x =25
x in a(2): 26      // inside a() method, increase the x by preincrement operator "++x" so x=26
x in b(1): 1       // inside b() method , it is using the instance variable x so value will be 1

x in b(2) 10     // inside b() method, multiplying x with 10 so value will be 10
x in a(1): 25   // inside a() method // inside a method ,local variable got the highest priority so x =25
x in a(2): 26      // inside a() method, increase the x by preincrement operator "++x" so x=26

x in b(1): 10 // inside b() method ,it is using the instance variable...previously the value was 10 so the present value will be 10
x in b(2) 100 // inside b() method,multiplying with 10 so value will be 100
x in Scope(2): 5 //inside class a, sysout will be called
y in main(1) 2 //main() method, main method sysout will be called
y in main(2) 2 //main() method,main method sysout will be called

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