how can i count and display the distinct values in this array? void sorting(int

Question

how can i count and display the distinct values in this array?

void sorting(int a[], int j)
{
   for(int i = 0; i < j; i++)
   {
       for(int k = 0; k < j; k++)
       {
           if(a[i] > a[k])
           {
               int temp;
               temp = a[i];
               a[i] = a[k];
               a[k] = temp;
           }
       }
   }
}

void count(int a[], int j)
{
   int occurence = 0;
   cout << "N" << "    Count" << endl;
   for(int i = 1; i < j; i++)
   {
       cout << a[i] << "     ";
       for(int k = 1; k < j; k++)
       {
           if(a[i] == a[k])
           {
               occurence++;
           }
           else
           {
               occurence = 1;
           }
       }
       cout << occurence << endl;
   }

}

Explanation / Answer

void count(int a[], int j)
{
int occurence = 0;
cout << "N" << " Count" << endl;
for(int i = 1; i < j; i++)
{
cout << a[i] << " ";
for(int k = 1; k < j; k++)
{
if(a[i] == a[k])
{
occurence++;
}
}
cout << occurence << endl;
}

void distinct(int a[] , int j){
int distinct=0;
for(int i=1;i<j;i++){
for(int k=1;k<j;k++){
if(a[i]==a[k]){
distinct++;
}
}
if(distinct==1){
cout<<a[i];
}
}
}

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