What is the consensus for this set of sequences? 5’-TTGCCGACTT-3’ 5’-ATGGCGTCTT-

Question

What is the consensus for this set of sequences?
5’-TTGCCGACTT-3’
5’-ATGGCGTCTT-3’
5’-ATGCCGACTT-3’
5’-ATGTCGACCT-3’
5’-TTGCCGACTT-3’
5’-ATGCCGACTT-3’
5’-TCGCCGAGTT-3’


a. 5’-TTGCCGACTT-3’
b. 5’-ATGGCGTCTT-3’
c. 5’-ATGCCGAGTT-3’
d. 5’-ATGTCGACCT-3’
e. 5’-TTGCCGACTT-3’
f. 5’-ATGCCGACTT-3’
g. 5’-TCGCCGAGTT-3’
h. 5’-AACTCGGCGA-3’

What do FISH and splicing have in common?

A They both act on DNA.
B They both utilize complementarity to find sequences.
C They both operate only in a 5’ to 3’ direction.
D They both only happen in vitro.
E They can both only happen ONCE on any given nucleic acid strand.

How many amino acids make up the protein encoded by a pre-mRNA that 10,327 bases long, contains 175 bases of 5’-untranslated sequence at the
bases of 3’-untranslated sequence beyond the stop codon, has 5692 bases of intron sequence removed, and finally has 200 bases of poly A added?

Explanation / Answer

consensus for these set of sequences is a. 5’-TTGCCGACTT-3’
FISH and splicing having the same character is that B They both utilize complementarity to find sequences. Given that pre-mRNA is having 10,327 bases long and it containing 175 bases of untranslated sequence 5692 bases of introns and 200 bases of poly A All these bases do not undergo transcription so. they dont give mRNA Apart from them remaining code for functional mRNA 10,327 - (175 + 5692 + 200) 10,327 - 6067 = 4260 So, total coding bases are 4260. The number of codons will be = 4260 / 3 = 1420 Total codons are 1420 which code for a specific amino acid. In them one code for stop codon which does not give amino acid. Finally there will be 1419 amino acids that make up the protein.

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