A computer has 64-KB virtual address space and 32-KB physical address space. The

Question

A computer has 64-KB virtual address space and 32-KB physical address space. The page size is 4 KB. At an instant ti , the mapping between virtual address space and physical address space is shown in Fig.2. Answer the following questions.

1) Compute virtual page number and offset for the virtual addresses 4000, 8200, 16000, and 48000.

2) Compute the physical address for the virtual addresses 4000, 8200, 16000, and 48000.

A computer has 64-KB virtual address space and 32-KB physical address space. The page size is 4 KB. At an instant ti , the mapping between virtual address space and physical address space is shown in Fig.2. Answer the following questions. 1) Compute virtual page number and offset for the virtual addresses 4000, 8200, 16000, and 48000. 2) Compute the physical address for the virtual addresses 4000, 8200, 16000, and 48000.

Explanation / Answer

If the operating system decided to evict page frame 1, it would load virtual page 8 at physical address 4K and make two changes to the MMU map.

First, it would mark virtual page 1

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