In java, Write an expression that continues to bid until the user enters \'n\'.

Question

In java, Write an expression that continues to bid until the user enters 'n'.

import java.util.Random;
import java.util.Scanner;

public class AutoBidder {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
Random randGen = new Random();
char keepGoing = '-';
int nextBid = 0;

randGen.setSeed(5);
while (/* Your solution goes here */) {
nextBid = nextBid + (randGen.nextInt(10) + 1);
System.out.println("I'll bid $" + nextBid + "!");
System.out.print("Continue bidding? ");
keepGoing = scnr.next().charAt(0);
}
System.out.println("");

return;
}
}

Explanation / Answer

import java.util.Random;
import java.util.Scanner;

public class AutoBidder {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
Random randGen = new Random();
char keepGoing = '-';
int nextBid = 0;

randGen.setSeed(5);
while (keepGoing != 'n') {
nextBid = nextBid + (randGen.nextInt(10) + 1);
System.out.println("I'll bid $" + nextBid + "!");
System.out.print("Continue bidding? ");
keepGoing = scnr.next().charAt(0);
}
System.out.println("");

return;
}
}

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