USING C++ Given two POSITIVE integers num1 and num2 1. Calculate the product of

Question

USING C++

Given two POSITIVE integers num1 and num2 1. Calculate the product of num1 and num2 2. Calculate num 1/num2 (integer division) 3. Calculate num 1%num2 (remainder) IMPORTANT - YOU CANNOT USE * (multiply), % (mod) or / (integer div) in your solutions. PLEASE USE WHILE LOOPS and ADDITION (+) and SUBTRACTION (-) to do the above calculations. Test with num1 = 179 num2 = 12 Example Execution: Please enter first positive integer: 179 Please enter second positive integer: 12 The product of 179 and 12 is 2148. The div of 179 and 12 is 14. The remainder when 179 is div by 12 is 11.

Explanation / Answer

#include <iostream>

using namespace std;

int main ()
{

   int num1 = 0, num2 = 0, product = 0, div = 0, temp = 0, remainder = 0;

   cout << "Please enter first positive integer: " << endl;
   cin >> num1;
   cout << "Please enter second positive integer: " << endl;
   cin >> num2;

   for (int i = 1; i <= num2; i++)
   {
       product = product + num1;
   }
   cout << "The product of " << num1 << " and " << num2 << " is " << product << endl;

   temp = num1;
   while (num1 >= num2)
   {
        num1 = num1 - num2;
        remainder = num1;
        div++;
   }
   cout << "The division of " << temp << " and " << num2 << " is " << div << endl;
   cout << "The remainder of " << temp << " and " << num2 << " is " << remainder << endl;

   return 0;
}

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