Consider the following algorithm. How many times does a beep statement get execu

Question

Consider the following algorithm.

How many times does a beep statement get executed?

for

i {1, 2, 3, 4, 5}

do      beep           for

j {1, 2, 3}

do                beep           for

k {1, 2, 3, 4}

do                for

l {1, 2, 3, 4, 5, 6}

do                         beep                     for

m {1, 2, 3, 4}

do               beep Consider the following algorithm. for i epsilon {1, 2, 3, 4, 5} do beep for j epsilon {1, 2, 3} do beep for k epsilon {1, 2, 3, 4} do for / epsilon {1, 2, 3, 4, 5, 6} do beep for m epsilon {1, 2, 3, 4} do beep How many times does a beep statement get executed?

Explanation / Answer

for
i is in {1, 2, 3, 4, 5}   
do
beep // A
for
   j is in {1, 2, 3}
   do
       beep // B
for
   k is in {1, 2, 3, 4}
   do
   for
       l is in {1, 2, 3, 4, 5, 6}
       do
   beep // C
   for
       m is in {1, 2, 3, 4}
       do
       beep // D

The outermost loop(loop variable: i) runs 5 times.
So, the beep in line A runs 5 times.

The beep in line B runs 3 times for every value of i.
So, total number of times beep in line B runs = 5 * 3 = 15.

The beep in line C runs 6 times for every value of k.
So, total number of times beep in line C runs = 5 * 4 * 6 = 120.

The beep in line D runs 4 times for every value of k.
So, total number of times beep in line C runs = 5 * 4 * 4 = 80.

Total number of times beep statement gets executed = 5 + 15 + 120 + 80 = 225

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