Determine the output for each part below by hand (do not compile the programs).

Question

Determine the output for each part below by hand (do not compile the programs).

Part A

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int i = 0; i < R; i++)

{   for (int j = 0; j < C; j++)

        cout << setw(3) << A[i][j];

    cout << endl; }

Part B

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int i = 1; i < R; i++)

{   for (int j = 1; j < C; j++)

        cout << setw(3) << A[i][j];

    cout << endl; }

Part C

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int j = 0; j < C; j++)

{   for (int i = 0; i < R; i++)

        cout << setw(3) << A[i][j];

    cout << endl; }

Part D

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int i = R-1; i >= 0; i--)

{   for (int j = C-1; j >= 0; j--)

        cout << setw(3) << A[i][j];

    cout << endl; }

Part E

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int i = 0; i < R; i++)

{   for (int j = 0; j < i+1; j++)

        cout << setw(3) << A[i][j];

    cout << endl; }

Part F

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int i = 0; i < R; i++)

{   for (int j = 0; j < C; j++)

        if(i>=j)cout<<setw(3)<<A[i][j];

    cout << endl; }

Part A

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int i = 0; i < R; i++)

{   for (int j = 0; j < C; j++)

        cout << setw(3) << A[i][j];

    cout << endl; }

Part B

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int i = 1; i < R; i++)

{   for (int j = 1; j < C; j++)

        cout << setw(3) << A[i][j];

    cout << endl; }

Part C

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int j = 0; j < C; j++)

{   for (int i = 0; i < R; i++)

        cout << setw(3) << A[i][j];

    cout << endl; }

Part D

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int i = R-1; i >= 0; i--)

{   for (int j = C-1; j >= 0; j--)

        cout << setw(3) << A[i][j];

    cout << endl; }

Part E

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int i = 0; i < R; i++)

{   for (int j = 0; j < i+1; j++)

        cout << setw(3) << A[i][j];

    cout << endl; }

Part F

const int R = 4, C = 3;

double A[R][C]={1,2,3,4,5,6,7,8,9,10,11,12};

for (int i = 0; i < R; i++)

{   for (int j = 0; j < C; j++)

        if(i>=j)cout<<setw(3)<<A[i][j];

    cout << endl; }

Explanation / Answer

partA
Whole array will be printed

1 2 3
4 5 6
7 8 9
10 11 12

partB
Whole array except the 1st column and the first row will be printed(because the loops are starting from 0)

5 6
8 9
11 12

partC
Whole array will be printed, but as a transpose of the output in partA(because inner and louter loops are interchanged)

1 4 7 10
2 5 8 11
3 6 9 12

partD
The array will pe printed in such a way that only the first 'k' elements of the 'k'th row are printed. Also, the last element in the last row will be garbage value because A[3][3] is not an element of an array

1
4 5
7 8 9
10 11 12<garbage value>

partE
The array will pe printed in such a way that only the first 'k' elements of the 'k'th row are printed. Also, the 4th row will have 3 elements because of the if condition

1
4 5
7 8 9
10 11 12

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