Write a method isExclusive that accepts a map whose keys and values are strings

Question

Write a method isExclusive that accepts a map whose keys and values are strings as a parameter and returns true if no two keys map to the same value (and false if any two or more keys do map to the same value). For example, if the map contains the following key/value pairs, your method would return true: {Mary=Bailey, Stuart=Peter, Jessica=Miller, Amanda=James, Hal=Perkins}. But calling it on the following map would return false, because of two mappings for Perkins and Reges: {Kendrick=Perkins, Stuart=Reges Jessica=Miller, Bruce=Reges, Hal=Perkins}.

Write a method removeEvenLength that accepts a set of strings as a parameter and that removes all of the strings of even length from the set.

Explanation / Answer

Program code:

1)

def isExclusive(mymap):

     for i in range(0,len(mymap)):

          for j in range(i+1,len(mymap)):

               if list(mymap.values())[i]==list(mymap.values())[j]:

                    return False        

     return True

mymap={"Kendrick":"Perkins", "Stuart":"Reges" ,"Jessica":"Miller", "Bruce":"Reges", "Hal":"Perkins"}

flag=isExclusive(mymap)

print(flag)

mymap={'Marty':'Stepp', 'Stuart':'Reges', 'Jessica':'Miller', 'Amanda':'Camp', 'Hal':'Perkins'}

flag=isExclusive(mymap)

print(flag)

Sample output:

False

True

2)

def removeEvenLength(myList=[]):    

     length=len(myList)

     strings=""

     k=0

     while k < len(myList):

          strings=myList[k]         

          if (len(strings)%2)==0:

              del myList[k]

          k=k+1

     for k in myList:

          print(k)

newList=['Kendrick', 'Perkins', 'Stuart', 'Jessica', 'Bruce', 'Miller', 'Amanda']

removeEvenLength(newList)

Sample Output:

Perkins

Jessica

Bruce

Amanda

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