Please help me and if you could show your work that would help so much, Thank yo

Question

Please help me and if you could show your work that would help so much, Thank you!

[13 Points] Dihybrid cross/Chi-square analysis: In Drosophila melanogaster, the normal wing allele (N) is dominant over the vestigial wing allele (n) and hairless body (H) is dominant over hairy body 1. Phenotype Number of observed individuals N_hh nnH nnhh 537 182 175 Total: 960 Conduct a chi-square test to check whether the data conform tothe Mendelian law of independent assortment. Be sure to include the number of degrees of freedom and the p-value based on which you'll accept or reject the hypothesis of independent assortment. Use attached page If this were a test cross of the F1, what will change in your expected values? Give the exact value for each phenotype e) Test whether Mendel's law of segregation applies to normal wings (N_ vs. nn). Use attached page f) Assuming the hypothesis of independent assortment was rejected, what might be a very likely explanation? What will the expected number of each phenotype depend upon? g)

Explanation / Answer

Number of phenotypes = 22 = 4

Number of genotypes = 32 = 9

observed

ratio

expected

ratio

expected

no.

Degrees of freesom = number of phenotypes - 1

4-1 =3

phenotype observed no.

observed

ratio

expected

ratio

expected

no.

(obs no.- exp. no )2 / exp. no N_H_ 537 537/66=8.13 9 960x9/16=540 (537-540)2/540=0.016 N_hh 182 182/66=2.75 3 960x3/16=180 (182-180)2/180=0.022 nnH_ 175 175/66=2.65 3 960x3/16=180 (175-180)2/180=0.138 nnhh 66 66/66=1.0 1 960x1/16=60 (66-60)2/60=0.6 Total 960 chisquare value 0.776

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