Roman Numeral Converter - C++ Write a program to read in Old Roman numerals and

Question

Roman Numeral Converter - C++

Write a program to read in Old Roman numerals and print out their value (base 10 numbers). Old Roman numerals do not have a smaller value in front of a larger one.

Example input:             Result:
III                                  III = 3
V                                   V = 5
XVIII                               XVIII = 18
MCCXXVI                    MCCXXVI = 1226

I is 1
V is 5
X is 10
L is 50
C is 100
D is 500
M is 1000

Cannot use arrays or classes as we have not covered them yet. Must use a while loop, and a switch. Use the enter key as the escape from the loop. (Empty line enter key to escape). Display must show what was entered plus the results.

Explanation / Answer

#include <iostream>
using namespace std;

int cal(char ch){
   if (ch == 'I') return 1;
   if (ch == 'V') return 5;
   if (ch == 'X') return 10;
   if (ch == 'L') return 50;
   if (ch == 'C') return 100;
   if (ch == 'D') return 500;
   if (ch == 'M') return 1000;
}

int main() {
   string s;
   int i;
   while(true){
       cin >> s;
       i = 0;
       for (int j = 0; j < s.length(); j++){
           i += cal(s[j]);
       }
       cout << s << " " << i << endl;
   }
   return 0;
}

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