1 LotteryPrinter Write a program LotteryPrinter that picks a combination in a lo

Question

1 LotteryPrinter Write a program LotteryPrinter that picks a combination in a lottery. In this lottery, players can choose 6 numbers (possibly repeated) between 1 and 49. Construct an object of the Random class and invoke an appropriate method to generate each number. (In a real lottery, repetitions aren't allowed, but we haven't yet discussed the programming constructs that would be required to deal with that problem.) Here is a sample run. Play this combination-it'll make you rich! Your lotter number is: 35 32 5 4 45 25 Use the skeleton shown below for your program. import java . util .Random; public class LotteryPrinter { public static void main(String 11 args) { code goes here

Explanation / Answer

working java code

import java.util.Random;

public class LotteryPrinter {
public static void main(String[]args) {
int setCount = 5; // Number of sets of lucky numbers.
int setSize = 6; // Number of lucky numbers in the set.
int range = 49; // Assume selecting integers between 1 and range.
int lucky; // Holds a lucky number candidate.
int luckyCount; // Holds count of lucky numbers in a set.
  
for(int i = 0 ; i < setCount ; ++i) {
int lucky1 = 0; // Lucky numbers for the set of 6.
int lucky2 = 0;
int lucky3 = 0;
int lucky4 = 0;
int lucky5 = 0;
int lucky6 = 0;
  
luckyCount = 0; // Count of numbers found in the current set
while(luckyCount < setSize) {
// Generate a lucky number between 0 and 48 and add 1:
lucky = (int)(range*Math.random()) + 1;
switch(luckyCount) {
case 0: // It is the first one
lucky1 = lucky; // so just store it
luckyCount++; // and increment the count
break;
case 1: // For the second we must
if(lucky != lucky1) { // check that it is different from the first
lucky2 = lucky; // It is, so store it
luckyCount++; // and increment the count
}
break;
case 2: // For the third we check aginst the previous two
if(lucky != lucky1 && lucky != lucky2) {
lucky3 = lucky;
luckyCount++;
}
break;
case 3: // Check against the previous three...
if(lucky != lucky1 && lucky != lucky2 && lucky != lucky3) {
lucky4 = lucky;
luckyCount++;
}
break;
case 4: // Check against the previous four...
if(lucky != lucky1 && lucky != lucky2 && lucky != lucky3 && lucky != lucky4) {
lucky5 = lucky;
luckyCount++;
}
break;
case 5: // Check against the previous five...
if(lucky != lucky1 && lucky != lucky2 && lucky != lucky3 && lucky != lucky4 && lucky != lucky5) {
lucky6 = lucky;
luckyCount++;
}
break;
}
}
  
System.out.print(" Set " + (i + 1) + ":"); // Identify the set
  
System.out.print(" " + lucky1 + " " + lucky2 + " " + lucky3 + // and output the numbers
" " + lucky4 + " " + lucky5 + " " + lucky6);
  
}
}
}

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