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Parents phenotypes: female: long hair, skin pigment male: short hair, albino (no

ID: 66935 • Letter: P

Question

Parents phenotypes: female: long hair, skin pigment male: short hair, albino (no pigment) All offspring are: long hair, skin pigment Assume independent assortment, alleles are on different chromosomes. Which alleles are dominant? What are the genotypes of the parents? What are the mother's possible gametes? What are the father s possible gametes? Which genotype do the F1 have? FI were crossed together, draw a Punnett Square that shows all possible genotypes. Gametes from each FI parent are: What are the phenotypes? What are their ratios? What is the expected phenotypic ratio of a dihybrid cross of two double heterozygotes? What is the expected phenotypic ratio of a test cross for the FI generation?

Explanation / Answer

Suppose the allele for parent genotype "female having long hair -L and skin pigment- S"

Also "male having short hair- l and albino- s".

hence the cross is as follows: -

LLSS x llss

Mother possible gamete is LS and father possible gamete is ls

F1 generation- Since, the phenotype of LlSs (all progeny) is Long hair and skin pigment. Hence, the alleles dominants are L for long hair and S- skin pigment.

Cross between F1 involved as

Punnett square for F1 parents: -

Parents: Phenotype long hair and skin pigment X short hair and albino Parents genotype LLSS X llss Gametes LS ls F1 generation genotype All LlSs F1 generation phenotype All Long hair and Skin pigment
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