Compile and Run this code and explain what it is doing. Can someone help break t

Question

Compile and Run this code and explain what it is doing. Can someone help break this down and explain what this code is actually doing? Please and Thank You

void InsertionSort(int numbers[])
{
for (int i = 1; 1 < 13; i++){
System.out.print("Process"+i+"[ ");
int j = i;
int B = numbers[i];
  
while ((j > 0) && (numbers[j-1] > B )){
  
numbers[j] = numbers[j-1];
j--;
}
numbers[j] = B;
for(int j1 = 0; j1 <13; j1++)
System.out.print(numbers[j1]+" ");
System.out.println("]");
}
System.out.println(" After Insertion Sorting");
System.out.print("[");

for (int i=0; i<13;i++)
{
System.out.print(" " + numbers[i]);
}
System.out.println("]");
}

Explanation / Answer

// Function InsertionSort defined with 1 array having 13 elements as parameter
   void InsertionSort(int numbers[]){
       // loop through the array 13 times(because 13 elements are there)
       for(int i = 1; i < 13; i++){
           // Print the loop number
           System.out.print("Process" + i + "[ ");
           // set j = i
           int j = i;
           // store the element at ith index in B
           int B = numbers[i];
          
           // find the appropriate position for b in the first i places
           while((j > 0) && (numbers[j - 1] > B)){
               numbers[j] = numbers[j-1];
               j--;
           }
           // j is the required position
           // Now we set the element at jth position as B
           numbers[j] = B;
          // print the array in each step
           for(int j1 = 0; j1 <13; j1++)
               System.out.print(numbers[j1]+" ");
           System.out.println("]");
       }
       // print the final array after the loop ends
       System.out.println(" After Insertion Sorting");
       System.out.print("[");
       for (int i=0; i<13;i++){
           System.out.print(" " + numbers[i]);
       }
       System.out.println("]");
   }

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