JAVA Programming No Arrays please. The Program: You will randomly generate an ID

Question

JAVA Programming

No Arrays please.

The Program: You will randomly generate an ID number for the employee and then check to see if it is in use. ID's in use will be stored in a file.

Create a class called IDNumber, the code written must first generate an ID number in the format XXX-L where each X is a digit within the range 0-9 and the L is a letter within the range A-M.

Use a loop to generate digit by digit, then the ID number will then need to be put together in a String variable.

Remember do not use an array.

Explanation / Answer

package mani;

import java.io.FileNotFoundException;
import java.io.PrintWriter;
import java.util.Random;

public class testing {
  
public static void main(String[] args) throws FileNotFoundException{
String[] inuse=new String[10];
inuse[0]="123-A";
inuse[1]="345-B";
Random r=new Random();
String IDNumber="";
for(int i=0;i<3;i++){
   IDNumber=IDNumber+Integer.toString(r.nextInt(10));
}
PrintWriter writer = new PrintWriter("idnumber.txt");
writer.println("The first line");
writer.println("The second line");
writer.close();
IDNumber=IDNumber+"-";
char t=(char)(65+r.nextInt(13));
IDNumber=IDNumber+t;
for(String k:inuse){
   if(k==IDNumber){
       System.out.println("IDnumber in use!!!"+IDNumber);
       writer.write(IDNumber);
   }else{
       System.out.println("IDnumber not in use!!!"+IDNumber);
   }
}
}
}

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