Using Audrino, 1) write a sketch that prints the integers in inscreasing order f

Question

Using Audrino,

1) write a sketch that prints the integers in inscreasing order from 1 to n then in decreasing order from n-w to 1. Print all values in a single row and leave at least 2 blank spaces between each value on the row. In other words, write the program to create the following output in Serial Monitor when n=7 (1 2 3 4 5 6 7 6 5 4 3 2 1) In your solution declare n as variable.

2) Extend the preceeding program by repeating the print out values of n=3,5,7,9 in the same program. The output of your program in the serial moinitor should look ilike this

(1 2 3 2 1

1 2 3 4 5 4 3 2 1

1 2 3 4 5 6 7 6 5 4 3 2 1)

1 2 3 4 5 6 7 8 9 8 7 6 5 4 3 2 1)

Explanation / Answer

Program:1

int n = 3; //
int i = 1;
int j = n-1;
void setup() // run once, when the sketch starts
{
Serial.begin(9600); // set up Serial library at 9600 bps
}

void loop() // run over and over again
{   
// print out the state of the button:
   if(i<=n) //printing forward
   {
        Serial.print(i+" ");
        i=i+1;
   }
   if(i>n) // printing reverse
   {
        Serial.print(j+" ");
        j=j-1;
   }
   delay(1000); // delay in between reads for stability
}

Program 2:

int n = 3;
int i = 1;
void setup() // run once, when the sketch starts
{
Serial.begin(9600); // set up Serial library at 9600 bps

}

void loop() // run over and over again
{   
// print out the state of the button:
   if(i<=n)//printing forward
   {
        Serial.print(i+" ");
        i=i+1;
   }
   if(i==n)
   {
       j=n-1;
   i=i+1;
   }
   if(i>n && j>0) // printing reverse
   {
        Serial.print(j+" ");
        j=j-1;
   }
   if(j==0)
   {
       Serial.println("");
       if(n<9)
       n=n+2; // increment n to have values like 3, 5, 7,9
       i=1;
   }
   delay(1000); // delay in between reads for stability
}

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