The Ksp for a substanceAB 3 is 7.8x10 -10 . What is the [B]? Please show steps.

Question

The Ksp for a substanceAB3 is 7.8x10-10. What is the [B]? Please show steps. :) The Ksp for a substanceAB3 is 7.8x10-10. What is the [B]? Please show steps. :) Please show steps. :)

Explanation / Answer

1) This is solubility question, assuming that it completelydissociates: AB3--> A+ 3B And Ksp= 7.8x10-10 2) Just do an ice table (or RICE table) Reaction: AB3--> A+ 3B Initial       solid Change    solid     +x    +3x Equil.      solid +x    +3 Ksp= products/reactants which is 7.8x10-10= (3x)3(x) 3) solids and liquids do not account in the equilibriumequation 4) Then solve for x then plug X back in 3X which accounts for 3times the amount of B for every 1 mole of AB3dissociated.

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