Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

This is a visualization problem, but my computer isn\'t letting mecopy paste it

ID: 676089 • Letter: T

Question

This is a visualization problem, but my computer isn't letting mecopy paste it onto the website, so I am going to do my best toprovide the needed information.
The problem/question is: If the total pressure of themixture visualized is 1360 torr, calculate the partial pressure(torr) of CF4.
The image contains thefollowing: 12 dots of CF4, which means 12moles or CF4, correct? 11 dots of C2H6, which means 11moles of C2H6, correct?
The problem/question is: If the total pressure of themixture visualized is 1360 torr, calculate the partial pressure(torr) of CF4.
The image contains thefollowing: 12 dots of CF4, which means 12moles or CF4, correct? 11 dots of C2H6, which means 11moles of C2H6, correct?

Explanation / Answer

Partial pressure of a componant in a mixture = Molefraction of that componant *Total pressure Mole fraction of CF4 = 12 dots /(12+11)dots                                   =0.5217 Since ,mole fraction is a ratio , dont worry about units. Mole fraction of C2H6 = 11/(11+12)                                     =0.4783 Partial pressure of CF4 = 0.5217 *1360torr                                         =709.512 torr    Partial pressure of C2H6 = 0.4783*1360torr                                          =650.488torr    Partial pressure of C2H6 = 0.4783*1360torr                                          =650.488torr
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote