(a) 0.4 m NaCl 0.3 m Na 2 SO 4 0.5 m sucrose (nonelectrolyte) (b) 0.2 m HCl 0.2
ID: 676122 • Letter: #
Question
(a) 0.4 m NaCl 0.3 m Na2SO4 0.5 m sucrose (nonelectrolyte)
(b) 0.2 m HCl 0.2 m aceticacid 0.3 m KOH
(weak electrolyte)
(c) 0.5 m ethyleneglycol 0.4 mglucose 0.3 m BaCl2
(nonelectrolyte) (nonelectrolyte)
_________________________
(a) Highest BP: .4m NaCl
Lowest BP: .5 m surcrose
(b) Highest BP: ..3m KOH
Lowest BP: .2m acetic acid
(c) Highest BP: .3m BaCl2
Lowest BP: I am unsure
Could someone check this for me?? Thank you!!!
Explanation / Answer
The stronger the intermolecular forces, the higher the boilingpoint. Also account the "i" van't hoff factor. a. .4 m NaCl -> .4 x 2 = .8 .3 m Na2SO4 -> .3 x 3 = .9 (highest boiling point) .5 m sucrose -> .5 x 1 = .5 (lowest boiling point) b. .2 m HCl -> .2 x 2 = .4 .2 acetic acid -> .2 x 1 = .2 (lowest) .3 m KOH -> .3 x 2 = .6 (highest) c. .5 m ethlene glycol -> .5 x 1 = .5 .4 m glucose -> .4 x 1 = .4 (lowest) .3 m BaCl2 -> .3 x 3 = .9 (highest)
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