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(a) 0.4 m NaCl 0.3 m Na 2 SO 4 0.5 m sucrose (nonelectrolyte) (b) 0.2 m HCl 0.2

ID: 676122 • Letter: #

Question

(a)      0.4 m NaCl                          0.3 m Na2SO4                                             0.5 m sucrose (nonelectrolyte)

(b)      0.2 m HCl                            0.2 m aceticacid                                         0.3 m KOH

                                                           (weak electrolyte)

(c)       0.5 m ethyleneglycol          0.4 mglucose                                              0.3 m BaCl2

           (nonelectrolyte)                   (nonelectrolyte)

_________________________


(a) Highest BP: .4m NaCl

Lowest BP: .5 m surcrose


(b) Highest BP: ..3m KOH

Lowest BP: .2m acetic acid


(c) Highest BP: .3m BaCl2

Lowest BP: I am unsure


Could someone check this for me?? Thank you!!!

Explanation / Answer

The stronger the intermolecular forces, the higher the boilingpoint. Also account the "i" van't hoff factor. a. .4 m NaCl -> .4 x 2 = .8 .3 m Na2SO4 -> .3 x 3 = .9 (highest boiling point) .5 m sucrose -> .5 x 1 = .5 (lowest boiling point) b. .2 m HCl -> .2 x 2 = .4 .2 acetic acid -> .2 x 1 = .2 (lowest) .3 m KOH -> .3 x 2 = .6 (highest) c. .5 m ethlene glycol -> .5 x 1 = .5 .4 m glucose -> .4 x 1 = .4 (lowest) .3 m BaCl2 -> .3 x 3 = .9 (highest)