Can someone explain in detail all of the steps to do thisproblem? Benzene (C 6 H

Question

Can someone explain in detail all of the steps to do thisproblem?
Benzene (C6H6) burns in air to producecarbon dioxide and liquid water. Calculate the heat released (inkilojoules) per gram of the compound reacted with oxygen. Thestandard enthalpy of formation of benzene is 49.04 kJ/mol. Can someone explain in detail all of the steps to do thisproblem?
Benzene (C6H6) burns in air to producecarbon dioxide and liquid water. Calculate the heat released (inkilojoules) per gram of the compound reacted with oxygen. Thestandard enthalpy of formation of benzene is 49.04 kJ/mol.

Explanation / Answer

             2 C 6H 6 +  15 O2    ---------->   12CO2 +  6 H2O     The enthalpy of the reaction = Hf(products) - Hf (reactents)                                                =[ 12 (Hf (CO2)) + 6 (Hf (H2O)) ] - [ 2(Hf (C6H6)) + 15 ( Hf(O2)) ]                                                =[12(-393.51 kJ/mol) + 6 (-241.82 kJ/mol) ] - [ 2 (49.04kJ/mol) + 15 (0)]                                                =- 6271.12 kJ This is the heat released for 1 mole of benzene. Molar mass of benzene = 78.12 g/mol So heat released for 78.12 g is 6271.12 kJ Heat released for 1 g is   6271.12 /78.12 = 80.27 kJ

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