Question 14.28 states: The reaction between ethyl bromide(C 2 H 5 Br) and hydrox

Question

Question 14.28 states: The reaction between ethyl bromide(C2H5Br) and hydroxide ion in ethyl alcoholat 330 K, C2H5Br(alc) + OH-(alc)--> C2H5Br(l) + Br-(alc), isfirst order each in ethyl bromide and hydroxide ion. When[C2H5Br] is .0477 M and[OH-] is .100 M, the rate of disappearance ofethyl bromide is 1.7 x 10-7M/s.(a) What is the value of the rate constant?(b) What are the units of the rate constant?(c) How would the rate of disappearance of ethylbromide change if the solution were diluted by adding an equalvolume if pure ethyl alcohol to the solution? Question 14.28 states: The reaction between ethyl bromide(C2H5Br) and hydroxide ion in ethyl alcoholat 330 K, C2H5Br(alc) + OH-(alc)--> C2H5Br(l) + Br-(alc), isfirst order each in ethyl bromide and hydroxide ion. When[C2H5Br] is .0477 M and[OH-] is .100 M, the rate of disappearance ofethyl bromide is 1.7 x 10-7M/s.(a) What is the value of the rate constant?(b) What are the units of the rate constant?(c) How would the rate of disappearance of ethylbromide change if the solution were diluted by adding an equalvolume if pure ethyl alcohol to the solution?

Explanation / Answer

You must first find out the rate equation. since it says itis first order, the reation looks like this Rate = k[C2H5Br][OH-] you are given the rate of disappearence. 1.7E-7 = k[C2H5Br][OH-] k = (1.7E-7) / (.0477M)(.100) A) k = 3.56E-5M-1S-1 B) M-1S-1   C) 1 / 4 the intial rate = 8.9E-6M-1S-1

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