A cylinder contains 2 lbm of an ideal gas wth a gas constant Rof 53 ft lbf/lbm o

Question

A cylinder contains 2 lbm of an ideal gas wth a gas constant Rof 53 ft lbf/lbm oR. The gas is initially at agauge pressure of 30 psi and temperature 100 oF. It is heated at constant volume until it reaches a temperature of300 oF and is then allowed to expand at constantpressure until its volume doubles. What is the pressure ofthe gas (psia) at the end of the heating process? What is thefinal temperature of the gas (oF) at the end of theexpansion. **I just need to know the process to solve foreverything** thanks A cylinder contains 2 lbm of an ideal gas wth a gas constant Rof 53 ft lbf/lbm oR. The gas is initially at agauge pressure of 30 psi and temperature 100 oF. It is heated at constant volume until it reaches a temperature of300 oF and is then allowed to expand at constantpressure until its volume doubles. What is the pressure ofthe gas (psia) at the end of the heating process? What is thefinal temperature of the gas (oF) at the end of theexpansion. **I just need to know the process to solve foreverything** thanks

Explanation / Answer

Initial volume , V1 = 2 lbm Initial pressure, P1 = 30 psi Initial temperature, T1 = 100 F = 310.92 K After heating, Temperature, T2 = 300 F = 422.03 K Pressure, P2 = ? We know P1 / T1 = P2 / T2 Pressure P2 = 30 psi * 422.03 K / 310.92 K                    =40.72 psi Then the gas is allowed to expand to double its initialvolume So initial volume, V1 = 2 lbm Initial temperature, T1 = 422.03 K So final volume , V2 = 2 V1 Temperature, T2 = ? V1 / T1 = V2 / T2 Substituting these values and simplifying will give the finaltemperature after expansion.

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