Assume that a student places 1.0 mol of solid PbI2 in 1.0 L of0.0010 M Pb^2+. Pa

Question

Assume that a student places 1.0 mol of solid PbI2 in 1.0 L of0.0010 M Pb^2+. Part of the lead iodide dissolves accordingto the following reaction:
PbI2 <---> Pb^2+ + 2I^-
After allowing the solution to sit for 30 minutes the studentdetermines that the iodide concentration was [I^-] = 0.0012 M. What is the Pb^2+?
please help, this is for a lab that is due today and we aretrying to figure it out but were are tied up.
PbI2 <---> Pb^2+ + 2I^-
After allowing the solution to sit for 30 minutes the studentdetermines that the iodide concentration was [I^-] = 0.0012 M. What is the Pb^2+?
please help, this is for a lab that is due today and we aretrying to figure it out but were are tied up. PbI2 <---> Pb^2+ + 2I^-
After allowing the solution to sit for 30 minutes the studentdetermines that the iodide concentration was [I^-] = 0.0012 M. What is the Pb^2+?
please help, this is for a lab that is due today and we aretrying to figure it out but were are tied up.

Explanation / Answer

Given original concentration of Pb^+2 = 0.0010 M

After addition of PbI2, 1 mole of Pb I2 ionizes to give 1mole of Pb^2+ and 2 moles of I ^-

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