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How do I determine the molar concentration of two substancesmixed together? For

ID: 677020 • Letter: H

Question

How do I determine the molar concentration of two substancesmixed together? For instance, I mixed Fe+3(aq) + SCN-(aq) = FeSCN+2(aq) Fe+3 solution had molarity of0.004M For the second solution, I mixed 1 g of KSCN in 15 mL ofdeionized water Then I mixed equal volumes of both of these solutions to getthe reaction above. How do I determine the molar concentration of two substancesmixed together? For instance, I mixed Fe+3(aq) + SCN-(aq) = FeSCN+2(aq) Fe+3 solution had molarity of0.004M For the second solution, I mixed 1 g of KSCN in 15 mL ofdeionized water Then I mixed equal volumes of both of these solutions to getthe reaction above.

Explanation / Answer

Given that The molarity of Fe+3 solution =0.004M The maolrity of KSCN = (mass of / molar mass) /volume of solution in liters                                      = (1 g / 97.1 g/mol) / 0.015 L                                       =0.6866 M Let us assume volumeof  Fe+3 solution is V1and volume of KSCN is V2    given that V1 = V2    Total volume of solution after mixing =V1 + V2                                                           =2 V1 The molarity Fe+3solution aftermixing = 0.004 M*V1/2V1                                                                 =0.002 M       The molarityFe+3solution after mixing = 0.6866M*V2/2V1                                                                = 0.3433M             (since V1 = V2)                                                                 =0.002 M The molarity Fe+3solution aftermixing = 0.004 M*V1/2V1                                                                 =0.002 M       The molarityFe+3solution after mixing = 0.6866M*V2/2V1                                                                = 0.3433M             (since V1 = V2)                                                                 =0.002 M                                                                 =0.002 M       The molarityFe+3solution after mixing = 0.6866M*V2/2V1                                                                = 0.3433M             (since V1 = V2)                                                                 =0.002 M
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