If 1304 g of a substance is dissolved in 2826 g of acetic acidsolvent, the boili

Question

If 1304 g of a substance is dissolved in 2826 g of acetic acidsolvent, the boiling point of the solution is125.89 oC. Calculate the apparent molar mass(g/mol) of substance. Molar Mass (g/mol) CH3COOH 60.05 Solvent Melting Point (oC) 16.60 Boiling Point (oC) 118.5 Kf (oC/m) 3.59 Kb (oC/m) 3.08 Molar Mass (g/mol) CH3COOH 60.05 Solvent Melting Point (oC) 16.60 Boiling Point (oC) 118.5 Kf (oC/m) 3.59 Kb (oC/m) 3.08 Molar Mass (g/mol) CH3COOH 60.05 Solvent Melting Point (oC) 16.60 Boiling Point (oC) 118.5 Kf (oC/m) 3.59 Kb (oC/m) 3.08

Explanation / Answer

      Let 'M' be the molar massof the substance .     molality of the solution = (1304 / M) x(1000 / 2826)    Elevation in the boiling point = Kb xmolality         125.89oC -118.5oC = 3.08 x ( 1304 / M) x (1000 / 2826)             The molar mass of thesubstance = 1927.51g / mol

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