3) Potassium perchlorate is prepared by the following sequenceof reactions: Cl2

Question

3) Potassium perchlorate is prepared by the following sequenceof reactions:
Cl2 (g) + 2 KOH (aq) à KCl (aq) + KClO (aq) + H2O(l) 3 KClO (aq) à 2 KCl (aq) + KClO3 (aq) 4 KClO3 (aq) à 3 KClO4 (aq) + KCl (aq) What mass of Cl2 (g) is required to produce 234 g ofKClO4? 3) Potassium perchlorate is prepared by the following sequenceof reactions:
Cl2 (g) + 2 KOH (aq) à KCl (aq) + KClO (aq) + H2O(l) 3 KClO (aq) à 2 KCl (aq) + KClO3 (aq) 4 KClO3 (aq) à 3 KClO4 (aq) + KCl (aq) What mass of Cl2 (g) is required to produce 234 g ofKClO4?

Explanation / Answer

All you need to do it take the grams of KClO4 and convertthem into moles of required!!
( 234g KClO4 / 138.55g/mol ) x [4mol KClO3] = 2.25mol KClO3                                                      3molKClO4 2.25mol [1mol KClO3] x [3mol KClO] = 1.69mol KClO3                4molKClO3      1mol KClO3 1.69mol KClO [1mol KClO] x [1mol Cl2] x[70.9g Cl2]   = 39.94g Cl2 needed                         3molKClO     1mol KClO    1mol Cl2 Hope this helps! -PilsnerPrincess ( 234g KClO4 / 138.55g/mol ) x [4mol KClO3] = 2.25mol KClO3                                                      3molKClO4 2.25mol [1mol KClO3] x [3mol KClO] = 1.69mol KClO3                4molKClO3      1mol KClO3 1.69mol KClO [1mol KClO] x [1mol Cl2] x[70.9g Cl2]   = 39.94g Cl2 needed                         3molKClO     1mol KClO    1mol Cl2 Hope this helps! -PilsnerPrincess

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