We preformed a lab to find the percent of chloride in an unknownsample. I\'m not

Question

We preformed a lab to find the percent of chloride in an unknownsample. I'm not sure if I am calculating the Molarity of theAg+. The lab objective says:

"A silver nitrate solution is standardized using primary-standardsodium chloride. An unknown sample is then analyzed for chloride,and its concentration is determined using this standardized silvernitrate solution."

My mass of NaCl was 1.0071 g. My average volume from 3 titrationswas 39.58 mL, 0.03958 L. I calculated 0.0172 moles of NaCl (I'm notsure if this is correct). I assumed this was the same as the molesof Cl- in solution, and also equal to the number ofmoles of Ag+ since it is a 1:1 relationship. Using thisand the avergae volume I calculated M to be 4.35x10-1M.

If anyone could check my calculations or tell me if I went wronganywhere I'd really appreciate it. Thanks!

Explanation / Answer

NaCl = 1.0071 g = 0.0172 moles In 0.03958 L volume strength of NaCl  =   0.435 M Ag+ + Cl - ---->  AgCl   molar ratio = 1:1 [Cl - ] = 0.435 M = [AgCl] Ya. your calculations are correct.

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