The reaction C 2 H 6 (g) C 2 H 4 (g) + H 2 (g), requires thatwork be done to mak

Question

The reaction C2H6(g) C2H4(g) + H2(g), requires thatwork be done to make it occur.
Calculate the minimummass, in grams, of hydrogen gas that would have to be burnedto form water vapor in order to provide the necessary work toproduce 188.0g of ethylene. The reaction C2H6(g) C2H4(g) + H2(g), requires thatwork be done to make it occur.
Calculate the minimummass, in grams, of hydrogen gas that would have to be burnedto form water vapor in order to provide the necessary work toproduce 188.0g of ethylene.

Explanation / Answer

   We Know that the given Reaction is :      C2H6 ------> C2H4 + H2         As from the aboveequation it is clear that 1 mole of ethane on decompositionproduces 1mole of ethylene and 1 mole of H2 gas.        The amount of hydrogengas produced reacts with Oxygen to form water-vapour.           Theamount of ethylene gas produced is 188.0 gm           number of moles of ethylene gas = 188.0 gm / 28gm / mole                                                                = 6.7142 moles           The number of moles of H2 formed isalso 6.7142 moles           The amount of H2 gas requiredis 6.7142 moles x 2 gm / moles                                                                   = 13.4284 gm.                         H2 + 1 / 2 O2  -----> H2O ( g )                  The amount of H2O formed is 6.7142moles x 18 gm / moles                                                                  = 120.85 gm.         As from the aboveequation it is clear that 1 mole of ethane on decompositionproduces 1mole of ethylene and 1 mole of H2 gas.        The amount of hydrogengas produced reacts with Oxygen to form water-vapour.           Theamount of ethylene gas produced is 188.0 gm           number of moles of ethylene gas = 188.0 gm / 28gm / mole                                                                = 6.7142 moles           The number of moles of H2 formed isalso 6.7142 moles           The amount of H2 gas requiredis 6.7142 moles x 2 gm / moles                                                                   = 13.4284 gm.                         H2 + 1 / 2 O2  -----> H2O ( g )                  The amount of H2O formed is 6.7142moles x 18 gm / moles                                                                  = 120.85 gm.

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