Q-3) calculate the concentration of the acid (or base)remaining is solution when

Question

Q-3) calculate the concentration of the acid (or base)remaining is solution when 10.7 ML of 0.223 M HNO3 is added to 16.3ML of 0.238 m NaOH. Number______________________M Q-4) you are asked to preapare a 1.35 M solution of Nacl,starting with 265.0 grams of Nacl, what should be the total volumeof the solution (in L)? number______________liters. Q-3) calculate the concentration of the acid (or base)remaining is solution when 10.7 ML of 0.223 M HNO3 is added to 16.3ML of 0.238 m NaOH. Number______________________M Q-4) you are asked to preapare a 1.35 M solution of Nacl,starting with 265.0 grams of Nacl, what should be the total volumeof the solution (in L)? number______________liters.

Explanation / Answer

QUESTION 3 HNO3 + NaOH -> NaNO3 + H2O n(HNO3) = cv = 0.223 x 0.0107 = 2.386 x10-3mol n(NaOH) = cv = 0.238 x 0.0163 = 3.879 x 10-3mol HNO3 is the limiting reagent n(NaOH) in excess = (3.879 - 2.386) x 10-3 = 1.493 x10-3 mol Total volume of solution = 16.3 + 10.7 = 27mL = 0.027L c(base in excess) = n/v = (1.493 x 10-3 ) / 0.027 =0.0553M QUESTION 4 n(NaCl) = m/M = 265/58.44 = 4.5346mol c(NaCl) = n/v 1.35 = 4.5346/v v(solution) = 3.3589L Hope this helps!

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