5. Calculate H° for: BaCO 3 (s) BaO(s) + CO 2 (g) using the data given below 2Ba

Question

5. Calculate H° for: BaCO3(s) BaO(s) + CO2(g) using the data given below

2Ba(s) + O2(g) 2BaO(s)      H° = -1107.0kJ
Ba(s) + CO2(g) + ½O2(g) BaCO3(s)      H° =-822.5 kJ: *

-1929.5 kJ

-284.5 kJ

269.0 kJ

537.0 kJ

5. Calculate H° for: BaCO3(s) BaO(s) + CO2(g) using the data given below

2Ba(s) + O2(g) 2BaO(s)      H° = -1107.0kJ
Ba(s) + CO2(g) + ½O2(g) BaCO3(s)      H° =-822.5 kJ: *

-1929.5 kJ

-284.5 kJ

269.0 kJ

537.0 kJ

Explanation / Answer

Flip around the second equation:   BaCO3 -> Ba + CO2 +1/2O2     H = -(-822.5KJ) = 822.5 Half the first equation:       Ba + 1/2O2 -> BaO                    H = 1/2(-1107.0) = -553.5 Total the equation: BaCO3 -> CO2 +BaO         Add up H = 822.5 + -553.5 = 269.0 KJ

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