Write balanced equations for the following reactions in acidsolution. a) Ni 2+ (

Question

Write balanced equations for the following reactions in acidsolution.

a)      Ni2+ (aq) +IO4- (aq) --> Ni3+ (aq)I- (aq)

Explanation / Answer

-Identify reduction ( gain e) and oxidation (loss e) inreaction. a) Ni2+ (aq) + IO4-(aq) --> Ni3+ (aq) I- (aq) oxidation: Ni2+ --> Ni3+              --> Ni2+ --> Ni3+ + e-(1) reduction: IO4- --> I-                8H+ + IO4- + 8e- -->I- + 4H2O(2) (1) only has 1 electron while (2) has 8. Therefore,multiple(1) for 8. You have:                    8 Ni2+ --> 8Ni3+ +8 e-(3) Balance equation, (3)+(1) :             8 Ni2+ + 8H+ + IO4- +8e- --> I- + 4H2O +8Ni3+ +8e-           -->8 Ni2+ + 8H+ +IO4- --> I- + 4H2O+8Ni3+ b)Do the sameby identifying reduction-oxidation reduction: IO3- --> I-    -->6e- + 6H+ +IO3- --> I- +3H2O oxidation: Mn2+ -->MnO2--> 2H2O +Mn2+ --> MnO2 + 4H++ 2e- Do the same, you have equation: 6H+ + IO3- + 6H2O +3Mn2+ --> 3MnO2 +12H+ + I- + 3H2O --> IO3- + 3H2O +3Mn2+ --> 3MnO2 +6H+ + I- c) P4 (s) +Cl- (aq) --> PH3 (g) +Cl2 (g) Reduction: P4 -->PH3-->          P4 --> 4PH3               12e- + 12H+ + P4 -->4PH3 (1) Oxidation: Cl- -->Cl2              2Cl- --> Cl2 +2e-(2)balance number of electrons in (2) : 2* 6= 12e Balance:12e- + 12H+ +P4 + 12Cl- --> 6Cl2+12e- + 4PH3 --> 12H+ + P4 + 12Cl---> 6Cl2 + 4PH3

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.