For the following reaction: A+2B+3C products a) determine the rate law in the fo

Question

For the following reaction: A+2B+3C products a) determine the rate law in the form rate =k[A]a[B]b[C]c given thedata below . b) determine the value for the rate constant k withthe correct units. Initial Concentration(mol/L)                              Initial Rate (mol/(L.s))                                                                      A                 B               C Experiment 1 0.2 0.2 0.2 2.4        Experiment 2 0.4 0.3 0.2 9.6 Experiment 3 0.2 0.3 0.2 2.4 Experiment 4 0.2 0.4 0.6 7.2 a) determine the rate law in the form rate =k[A]a[B]b[C]c given thedata below . b) determine the value for the rate constant k withthe correct units. Initial Concentration(mol/L)                              Initial Rate (mol/(L.s))                                                                      A                 B               C Experiment 1 0.2 0.2 0.2 2.4        Experiment 2 0.4 0.3 0.2 9.6 Experiment 3 0.2 0.3 0.2 2.4 Experiment 4 0.2 0.4 0.6 7.2 Initial Concentration(mol/L)                              Initial Rate (mol/(L.s))

Explanation / Answer

     We Know that :         The given reactionis :            A+ 2B + 3C ---------> products        From the given data:           Dividethe expt. 3 by 1 we get :          ( 0.2 / 0.3)b    = 1                    b = 0          Divide theexpt. 2 by 1 we get :             ( 0.2 / 0.4 )a      =   (2.4 / 9.6 )                      a = 2          Divide expt .4 by 3 we get :                  ( 0.2 / 0.6 )c = ( 2.4 / 7.2 )                        c   = 1         The Rate law of the equation is :                Rate = K [ A ]2 [ C ]                K = Rate /   [ A ]2 [C ]                      = 2.4 M /s /   [ 0.2 M]2 [ 0.2 M ]                       =   300 M-2 s-1         The given reactionis :            A+ 2B + 3C ---------> products        From the given data:           Dividethe expt. 3 by 1 we get :          ( 0.2 / 0.3)b    = 1                    b = 0          Divide theexpt. 2 by 1 we get :             ( 0.2 / 0.4 )a      =   (2.4 / 9.6 )                      a = 2          Divide expt .4 by 3 we get :                  ( 0.2 / 0.6 )c = ( 2.4 / 7.2 )                        c   = 1         The Rate law of the equation is :                Rate = K [ A ]2 [ C ]                K = Rate /   [ A ]2 [C ]                      = 2.4 M /s /   [ 0.2 M]2 [ 0.2 M ]                       =   300 M-2 s-1

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.