At a particular time, we observethat the reaction 2N2O5( g ) 4NO2( g )+ O2( g )

Question

At a particular time, we observethat the reaction 2N2O5(g) 4NO2(g)+ O2(g) isforming NO2 at the rate of 0.0072 M/s.(a)What is the rate of change of [O2] at this time?(b)What is the rate of change of [N2O5] at thistime? Please show/ explain steps At a particular time, we observethat the reaction 2N2O5(g) 4NO2(g)+ O2(g) isforming NO2 at the rate of 0.0072 M/s.(a)What is the rate of change of [O2] at this time?(b)What is the rate of change of [N2O5] at thistime? Please show/ explain steps Please show/ explain steps

Explanation / Answer

Unless I'm that rusty on chemistry, this should be simply a matter of division.  Since 4NO2s form for every 2N2O5 broken down, the rate of change of N2O5 is half that of NO2: .0072/2=.0036M/s (this is the part b answer, and it should be negative as well since the N2O5 is being depleted).  Also, since only 1O2 is formed for each 4NO2s formed, it forms at one quarter the rate of NO2: .0072/4=.0018M/s (answer for part a).

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