A ground state H-atom absorbs a photon ofwavelength 60.69 nm, and its electron a

Question

A ground state H-atom absorbs a photon ofwavelength 60.69 nm, and its electron attains a higher energylevel. The atom then emits two photons: one of wavelength 2408 nmto reach an intermediate level, and a second to reach the groundstate. What was the wavelength of the second photon emitted? A ground state H-atom absorbs a photon ofwavelength 60.69 nm, and its electron attains a higher energylevel. The atom then emits two photons: one of wavelength 2408 nmto reach an intermediate level, and a second to reach the groundstate. What was the wavelength of the second photon emitted?

Explanation / Answer

According to 'law of conservation of energy '             E60.69nm = E2408nm +Eunknown    Formula : E = hc/          hc/60.69nm = hc/ 2408nm +hc/unknown               1/ 60.69nm = 1/2408nm +1/unknown               1/ 60.69nm  - 1/2408nm =1/unknown                 1/ 60.69nm  - 1/2408nm   =1/unknown                   0.0164nm-1 - 4.15e-4  = 1/unknown                  unknown = 40.48nm

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