Hello, I have no idea how to set this one up. I\'ve usedmy textbook as a guide,
ID: 679804 • Letter: H
Question
Hello, I have no idea how to set this one up. I've usedmy textbook as a guide, but I'm not getting anywhere. Anyhelp would be appreciated. Thanks. -When 25.0 mL of 0.640 M H2SO4 is addedto 25.0 mL of 1.28 M KOH in a coffee-cup calorimeter at23.50°C, the temperature rises to 30.17°C. CalculateH of this reaction. (Assume that the total volume isthe sum of the individual volumes and that the density and specificheat capacity of the solution are the same as for purewater.) - Find: 1. H per mole ofH2SO4 reacted. 2. H per mole of KOH reacted. Hello, I have no idea how to set this one up. I've usedmy textbook as a guide, but I'm not getting anywhere. Anyhelp would be appreciated. Thanks. -
When 25.0 mL of 0.640 M H2SO4 is addedto 25.0 mL of 1.28 M KOH in a coffee-cup calorimeter at23.50°C, the temperature rises to 30.17°C. CalculateH of this reaction. (Assume that the total volume isthe sum of the individual volumes and that the density and specificheat capacity of the solution are the same as for purewater.) - Find: 1. H per mole ofH2SO4 reacted. 2. H per mole of KOH reacted.
Explanation / Answer
H2SO4 + 2 KOH -> K2SO4 + H2O moles H2SO4 = (0.025L)*(0.640M) = 0.016 moles H2SO4 moles KOH = (0.025L)*(1.28M) = 0.032 moles KOH E=mc(T2-T2) = (25 ml + 25ml)*(1g/ml)*(1cal/gC)*(30.17C-23.50C... = 333.5 cal deltaH = (333.5cal)/(0.016 mole H2SO4) = 5.336 cal/mole H2SO4 deltaH = (333.5cal)/(0.032 mole KOH) = 10.672 cal.mol KOH PLEASE RATE
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