Vinegar is a dilute solution of acetic acid. A 15.64 mLsample of vinegar with a
ID: 679963 • Letter: V
Question
Vinegar is a dilute solution of acetic acid. A 15.64 mLsample of vinegar with a density of 1.06g/mL requires 24.80 mL of0.469 N KOH for titration. What is the percent by mass ofacetic acid in vinegar.Explanation / Answer
KOH + CH3COOH -> CH3COOK +H2O 0.469N KOH = 0.469M KOH (since KOH contains 1 OH-) n(KOH) = cv = 0.469 x 0.0248 = 0.01163mol n(CH3COOH) = n(KOH) = 0.01163mol m(CH3COOH) = nM = 0.01163 x 60.052 = 0.698g Density = mass/volume 1.06 = mass/15.64 Mass of solution = 16.5784g %mass = 0.698/16.5784 x 100% = 4.2% Hope this helps!
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