Can someone explain in detail how to do thisproblem? 0.50 mol CCl 4 gas is intro
ID: 680049 • Letter: C
Question
Can someone explain in detail how to do thisproblem? 0.50 mol CCl4 gas is introduced into a 10.0-Lflask. What fraction of the total volume of the flask is occupiedby CCl4 molecules? (Value of Van der Waalsconstant b for CCl4 = 0.138 L/mol )Answer: 0.0138 Can someone explain in detail how to do thisproblem? 0.50 mol CCl4 gas is introduced into a 10.0-Lflask. What fraction of the total volume of the flask is occupiedby CCl4 molecules? (Value of Van der Waalsconstant b for CCl4 = 0.138 L/mol )
Answer: 0.0138
Explanation / Answer
Formula: Volume occupied = V-nb Given data: V = 10.0L , n = 0.138 L/mol, n= 0.50mol Therefore, voulme occupied gas molecules =10.0L - (0.50mol*0.138L/mol) =10.0L - 0.069L = 9.931L Hence, fraction of totoal volume occupied gas volume =9.931/10.0 = 0.9931 Hence, fraction of totoal volume occupied gas volume =9.931/10.0 = 0.9931Related Questions
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