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When _____ of propane (C 3 H 8 ) gas isburned in excess oxygen, following the eq

ID: 681049 • Letter: W

Question

When _____ of propane (C3H8) gas isburned in excess oxygen, following the equation below,____kJ ofheat is evolved. C3H8 (g) + 5O2 (g) --->3CO2 (g) + 4H2O ( l ) How much water (grams) can be vaporized using this ____ amountof propane as fuel, giben the enthalpy of vaporization of water is40.1kJ/mol? When _____ of propane (C3H8) gas isburned in excess oxygen, following the equation below,____kJ ofheat is evolved. C3H8 (g) + 5O2 (g) --->3CO2 (g) + 4H2O ( l ) How much water (grams) can be vaporized using this ____ amountof propane as fuel, giben the enthalpy of vaporization of water is40.1kJ/mol?

Explanation / Answer

We Know that :       We Know that :     The given Reaction is :          C3H8 (g) + 5O2 (g) --->3CO2 (g) + 4H2O ( l )          The amount ofPropane taken for the combustion is 44 gm which on combustionin the precess of excess of oxygen               to evolvecorresponding moles of CO2 &H2O.                      Hreaction = Hproducts   - Hreactants                                = 3 x - 393.51 + 4 x -285.83 ) KJ - [ -103.85 + 5 (0) ]KJ                                 = - 2220 KJ of heat is evolved .             The Enthalpy ofVapourization of water is 40.1 KJ / mole .            The amount of heat released isequal to -2220 KJ / mole           The amount of waterget evaporated is = 2220 KJ / 40.1 KJ                                                                      = 55.36 gm of water gets evaporated .          As we Knowthat Vapourization of water is   mass of the waterx enthalpy of vapourization of water.     The given Reaction is :          C3H8 (g) + 5O2 (g) --->3CO2 (g) + 4H2O ( l )          The amount ofPropane taken for the combustion is 44 gm which on combustionin the precess of excess of oxygen               to evolvecorresponding moles of CO2 &H2O.                      Hreaction = Hproducts   - Hreactants                                = 3 x - 393.51 + 4 x -285.83 ) KJ - [ -103.85 + 5 (0) ]KJ                                 = - 2220 KJ of heat is evolved .             The Enthalpy ofVapourization of water is 40.1 KJ / mole .            The amount of heat released isequal to -2220 KJ / mole           The amount of waterget evaporated is = 2220 KJ / 40.1 KJ                                                                      = 55.36 gm of water gets evaporated .          As we Knowthat Vapourization of water is   mass of the waterx enthalpy of vapourization of water.
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