QuestionDetails: A 5.75-g quantity of a diprotic acid was dissolvedin water andm

Question

QuestionDetails: A 5.75-g quantity of a diprotic acid was dissolvedin water andmade up to exactly 275 mL. Calculate the molar mass of the acid if25.0 mL of the solution required 11.0 mL of 1.00 M KOH forneutralizaion. Number=_____________g/mol ********WILL RATE********* QuestionDetails: A 5.75-g quantity of a diprotic acid was dissolvedin water andmade up to exactly 275 mL. Calculate the molar mass of the acid if25.0 mL of the solution required 11.0 mL of 1.00 M KOH forneutralizaion. Number=_____________g/mol ********WILL RATE********* QuestionDetails: A 5.75-g quantity of a diprotic acid was dissolvedin water andmade up to exactly 275 mL. Calculate the molar mass of the acid if25.0 mL of the solution required 11.0 mL of 1.00 M KOH forneutralizaion. Number=_____________g/mol ********WILL RATE*********

Explanation / Answer

11mL of a 1M KOH solution means .011 mol KOH was used inneutralizing the acid. Since the acid is diprotic, this means therewas originally .0055 mol of the acid. Thus, .52275g / .0055mol =95.05g/mol, the molar mass of the acid.

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