A drop of Methyl Orange was added. For this indicator thesolution will be Red in

Question

A drop of Methyl Orange was added. For this indicator thesolution will be Red in high concentration ofH3O+ , and solution will turn yellow in highconcentration of H3O+ A.) Initially equilibrum was orange. What is the expectedcolor after adding NaC2H3O2 .Explain. B) Initially equilibrium was orange. What is the expectedcolor after adding a strong acind which donatesH3O+ A drop of Methyl Orange was added. For this indicator thesolution will be Red in high concentration ofH3O+ , and solution will turn yellow in highconcentration of H3O+ A.) Initially equilibrum was orange. What is the expectedcolor after adding NaC2H3O2 .Explain. B) Initially equilibrium was orange. What is the expectedcolor after adding a strong acind which donatesH3O+ A.) Initially equilibrum was orange. What is the expectedcolor after adding NaC2H3O2 .Explain. B) Initially equilibrium was orange. What is the expectedcolor after adding a strong acind which donatesH3O+

Explanation / Answer

A) NaC2H3O2 is a base so adding itwould make the H3O+ be lower because you havea higher concentration of OH-. It will be the color thatmethyl orange turns when H3O+ islower. B) Adding a strong acid is going to increase the concentration ofH3O+. It will be the color that methyl orangeturns when H3O+ is high. I think you have an error in how you wrote the color changesbecause you have high concentrations ofH3O+ for both colors. I think you meantlower instead of high in the second (yellow). So, writedown the colors as I explained above, given the information thatyou have. Hope this helps!

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