The element cesium (Cs) freezes at 28.4degrees Celsius, and its molar enthalpy h

Question

   The element cesium (Cs) freezes at 28.4degrees Celsius, and its molar enthalpy heat of fusion is fus= 2.09 kJ/mol. a. When molten cesium solidifies to Cs(s) at its normalmelting point, it S positive or negative? b. Calculate the value of S when 15.0g of Cs(l)solidifies at 28.4 degrees Celsius.    The element cesium (Cs) freezes at 28.4degrees Celsius, and its molar enthalpy heat of fusion is fus= 2.09 kJ/mol. a. When molten cesium solidifies to Cs(s) at its normalmelting point, it S positive or negative? b. Calculate the value of S when 15.0g of Cs(l)solidifies at 28.4 degrees Celsius.

Explanation / Answer

      a . When the molten cesiumsolidifies to Cs(s) it changes from disordered system toordered system . Since entropy increases with increase in thedisorder of the system , the entropy of this case is decreased.                     S = -ve .      b. T =28.4oC = 28.4 +273                               = 301.4 K            S = - 2.09 kJ/mol / 301.4K                   = -6.93 J /mol.K

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