1)Is this reaction endothermic, exothermic, orneither? 2 C(s) + O2 (g) ------> 2

Question

1)Is this reaction endothermic, exothermic, orneither?     2 C(s) + O2 (g) ------> 2CO (g) + 52.8 kcal

2) Is this reaction endothermic, exothermic, or neither? 2NH3 (g) + 22kcal ---> N2 (g) + 3 H2 (g)

3)How much heat is released by the combustion of 0.850 moles ofacetone by the following reaction?
2 C3H6O(l) + 8 O2(g) ----> 6 CO2 (g) + 6 H2 O(g) + 853.6kcal

4)How much heat is needed to convert 268.4 g of ferric oxide toiron according to this reaction?
2 Fe2O3(s) + 196.5 kcal ----> 4 Fe(s) + 3 O2(g)

5) How much heat will be generated if we produce 30.8 grams ofcarbon dioxide from this process?
C(s) + O2(g) -----> CO2(g) + 94.0 kcal
1)Is this reaction endothermic, exothermic, orneither?     2 C(s) + O2 (g) ------> 2CO (g) + 52.8 kcal

2) Is this reaction endothermic, exothermic, or neither? 2NH3 (g) + 22kcal ---> N2 (g) + 3 H2 (g)

3)How much heat is released by the combustion of 0.850 moles ofacetone by the following reaction?
2 C3H6O(l) + 8 O2(g) ----> 6 CO2 (g) + 6 H2 O(g) + 853.6kcal

4)How much heat is needed to convert 268.4 g of ferric oxide toiron according to this reaction?
2 Fe2O3(s) + 196.5 kcal ----> 4 Fe(s) + 3 O2(g)

5) How much heat will be generated if we produce 30.8 grams ofcarbon dioxide from this process?
C(s) + O2(g) -----> CO2(g) + 94.0 kcal

Explanation / Answer

1.   2 C(s) + O2 (g) ------> 2CO (g)+ 52.8 kcal is exothermic reaction becauseheat is released in this reaction. 2. 2 NH3 (g) + 22kcal ---> N2 (g) + 3 H2 (g)
   is endo thermic reaction becausereactants need 22 k Cal energy to form products as indicated by thereaction.
3. Heat released = (-853.6kJ/2mol)(0.860mol)                            = -367.05kJ 4. heat required = (268.4g/(159.69g/mol))(196.5kcal/2mol)                           = 152.82kcal 5. Heat released = (30.8g/(44g/mol))(94.0kCal/1mol)                              =65.8kCal 4. heat required = (268.4g/(159.69g/mol))(196.5kcal/2mol)                           = 152.82kcal 5. Heat released = (30.8g/(44g/mol))(94.0kCal/1mol)                              =65.8kCal

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