Oxygen masks for pruducing O 2 in emergencysituations contain potassium superoxi

Question

Oxygen masks for pruducing O2 in emergencysituations contain potassium superoxide, KO2. It reactswith CO2 and H2O in exhaled air to produceoxygen: 4 KO2(s) + 2 H2O(g) +4CO2(g) = 4 KHCO3(s) + 3O2(g) If a person wearing such a mask exhales 0.702 gCO2/min. how many grams of KO2 are consumedin five minutes? Oxygen masks for pruducing O2 in emergencysituations contain potassium superoxide, KO2. It reactswith CO2 and H2O in exhaled air to produceoxygen: 4 KO2(s) + 2 H2O(g) +4CO2(g) = 4 KHCO3(s) + 3O2(g) If a person wearing such a mask exhales 0.702 gCO2/min. how many grams of KO2 are consumedin five minutes?

Explanation / Answer

            4KO2(s)+ 2 H2O(g) + 4CO2(g) = 4 KHCO3(s)+ 3 O2(g) Mass of CO2 exhaled in 5 min = 5 min * ( 0.702 g / 1min)                                                =3.51 g Moles of CO2 = mass / molar mass                        =3.51 g / 44.01 g/mol                        =0.079 mol From the equation, we know 4 moles of KO2 are consumed by 4moles of CO2 So 0.079 mol of KO2 will be consumed by 0.079 mol ofCO2. Mass of KO2 consumed = moles * molar mass                                        =0.079 mol * 71.10 g/mol                                        =5.67 g

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