CAN SOMEONE PLEASE HEP ME WITH THESE EXMAPLEPROBLEMS? 1) A sample of O 2 gas wit
ID: 682465 • Letter: C
Question
CAN SOMEONE PLEASE HEP ME WITH THESE EXMAPLEPROBLEMS?1) A sample of O2 gas with a volume of 5.47 L wascollected at 239 °C. What is the volume of the gas if thetemperature is changed to -35 °C at constantpressure?
2) If a 230 mL sample of gas at 207 °C is allowed toexpand (at constant pressure) to a volume of 534 mL, what will bethe new temperature (in °C)?
CAN SOMEONE PLEASE HEP ME WITH THESE EXMAPLEPROBLEMS?
1) A sample of O2 gas with a volume of 5.47 L wascollected at 239 °C. What is the volume of the gas if thetemperature is changed to -35 °C at constantpressure?
2) If a 230 mL sample of gas at 207 °C is allowed toexpand (at constant pressure) to a volume of 534 mL, what will bethe new temperature (in °C)?
Explanation / Answer
1) A sample of O2 gas with a volume of 5.47 L wascollected at 239 °C. What is the volume of the gas if thetemperature is changed to -35 °C at constant pressure? Considering that the number of mol does not change, we can assumethat: i = initial f = final P = pressure in atm V = volume in L T = temperature in Kelvin (TKelvin = 273 +TCelcius) (Pi . Vi) / Ti = (Pf .Vf) / Tf Pi = Pf (constant pressure) (Pi . Vi) / Ti =(Pf . Vf) /Tf Vi / Ti = Vf / Tf Vi = 5,47L Ti = 239oC = 512K Vf = ? Tf = -35oC = 238 K (5,47) / (512) = Vf / (238) Vf = 2,54L 2) If a 230 mL sample of gas at 207 °C is allowed to expand (atconstant pressure) to a volume of 534 mL, what will be the newtemperature (in °C)? (Pi . Vi) / Ti = (Pf .Vf) / Tf Pi = Pf (constant pressure) (Pi . Vi) / Ti =(Pf . Vf) /Tf Vi / Ti = Vf / Tf Vi = 230 mL = 0,23 L Ti = 207oC = 480K Vf = 534 mL = 0,534L Tf = ? (0,23) / (480) = (0,534) / Tf 0,23 Tf = 256,32 Tf = 1114,43 K. But the question says in oC. Converting we have.. TKelvin = 273 + TCelcius 1114,43 = 273 + TCelcius TCelcius = 841,43oC
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