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Using the bondenthalpies tabulated below, calculate the enthalpy of reaction for

ID: 682541 • Letter: U

Question

Using the bondenthalpies tabulated below, calculate the enthalpy of reaction forthe combustion of hydrogen. Hint: The bond enthalpies areapproximate enthalpies needed to make or break a chemicalbond. 2H2(g) + O2(g) 2H2O(g)                  bond  H(kj)                                                                        H-H      436                                                                         O-H       464                                                                         O-O         138                                                                         0=0        498        Using the bondenthalpies tabulated below, calculate the enthalpy of reaction forthe combustion of hydrogen. Hint: The bond enthalpies areapproximate enthalpies needed to make or break a chemicalbond. 2H2(g) + O2(g) 2H2O(g)                  bond  H(kj)                                                                        H-H      436                                                                         O-H       464                                                                         O-O         138                                                                         0=0        498                                                                               H-H      436                                                                         O-H       464                                                                         O-O         138                                                                         0=0        498       

Explanation / Answer

                 2H2(g) + O2(g) 2H2O(g)             The enthalpy of the reaction is the energy of the bond beingbroken minus the energy of the bond being formed.     In this reaction two H-H bonds and one O-O bond is broken . Two O-H bonds are formed .              Hrxn =   [ 2H-H + O-O ] - [ 4 O-H]                              = [ 2 * 436 kJ + 138 kJ ] - [ 4 * 464 kJ ]                              = 1010 - 1856 kJ                              = - 846 kJ
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