Ehylene glycol is composed of 38.7% C, 9.7% of H, and 51.6% Oby mass. Its molar

Question

Ehylene glycol is composed of 38.7% C, 9.7% of H, and 51.6% Oby mass. Its molar massis 62.1g/mol. (a) What is theempirical formula of ethylene alcohol? (b) What is its molecularformula? Answer (a) CH3O, (b)C2H6O2 Can you show me steps of solving for the answers above? Can somebody help me with all the Practice questions in thisbook, Chemistry, The General Science, 10th Edition? 3.1through 3.20? Thanks Ehylene glycol is composed of 38.7% C, 9.7% of H, and 51.6% Oby mass. Its molar massis 62.1g/mol. (a) What is theempirical formula of ethylene alcohol? (b) What is its molecularformula? Answer (a) CH3O, (b)C2H6O2 Can you show me steps of solving for the answers above? Can somebody help me with all the Practice questions in thisbook, Chemistry, The General Science, 10th Edition? 3.1through 3.20? Thanks Can you show me steps of solving for the answers above? Can somebody help me with all the Practice questions in thisbook, Chemistry, The General Science, 10th Edition? 3.1through 3.20? Thanks

Explanation / Answer

In your book, 2.6 tells you that the empirical formula is therelative number of atoms of each element it contains. In 62.1 grams/mol of ethylene glycol, you have 38.7% Carbon,9.7% Hydrogen, and 51.6% Oxygen, which when multiplied out (bymaking the percents decimals) you have apporximately 24 grams ofCarbon, 6 grams of Hydrogen and 32.1 grams of Oxygen. Divide eachby their molar mass (24 grams of Carbon divided by 12.01 grams permole = approximately 2 mol). You end up with 2 mol of Carbon, 6 molof Hydrogen, and 2 mol of Oxygen. The empirical formula is thefewest number (in the correct ratio) to still make up the element.(In this case, it would be 1::2::1). The molecular formula is theactual number you already figured out (2::6::2). Hope that helps!Let me know if you need anything else.

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