in the nernst equation: E = E cell - .0591/n (log[H]/[Cu]), what is the value of

Question

in the nernst equation: E = E cell - .0591/n (log[H]/[Cu]), what is the value of n for the number of moles of electrons?the solution provided just leaves this value as n and does notindicate that we are trying to solve for n either. the questionasks to solve for E not n. How was n obtained? what is the value of n for the number of moles of electrons?the solution provided just leaves this value as n and does notindicate that we are trying to solve for n either. the questionasks to solve for E not n. How was n obtained?

Explanation / Answer

First things first, n is the number of moles of electrons. When youbalance your equations you should note that Cu needs 2 electrons aswell as H. That means that n=2. Hope this helps!

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