Rauolt\'s law is P =P o X A solution was made by adding 75.0 g of sucrose(C 12 H

Question

Rauolt's law is P =PoX A solution was made by adding 75.0 g of sucrose(C12H22O11) to 500.0 g of water ata temperature of 20oC. What's the number of moles of water in the solution and what'sthe mole fraction of water in the solution? Rauolt's law is P =PoX A solution was made by adding 75.0 g of sucrose(C12H22O11) to 500.0 g of water ata temperature of 20oC. What's the number of moles of water in the solution and what'sthe mole fraction of water in the solution? A solution was made by adding 75.0 g of sucrose(C12H22O11) to 500.0 g of water ata temperature of 20oC. What's the number of moles of water in the solution and what'sthe mole fraction of water in the solution?

Explanation / Answer

Moles of water = mass / molar mass                         =500 g / 18 g/mol                         =27.77 moles Moles of sucrose = 75 g / 342.3 g/mol                            =0.219 moles Total moles = 27.77 + 0.219 = 27.98 moles Mole fraction of water = moles of water / total moles                                    =27.77 moles / 27.98 moles                                     =0.9924

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