please,please someone help me i dont understand this atall! 1.)The heat of fusio

Question

please,please someone help me i dont understand this atall!
1.)The heat of fusion of water is 80 cal/g, the heat ofvaporization of water is 540 cal/g, and the specific heat of wateris 1.0 cal/deg/g. How many grams of ice at 0 ° could beconverted to steam at 100 °C by 8,890 calories of heat? please,please someone help me i dont understand this atall!
1.)The heat of fusion of water is 80 cal/g, the heat ofvaporization of water is 540 cal/g, and the specific heat of wateris 1.0 cal/deg/g. How many grams of ice at 0 ° could beconverted to steam at 100 °C by 8,890 calories of heat?

Explanation / Answer

8890 cal = xg*80cal/g +xg*(100-00C)*1.0cal/deg.g + xg * 540cal/g               = 80x + 100x + 540x               = 720x      x = 8890 / 720         = 12.34g Thus, using 8890cal energy we can 12.34 g of ice at 0Cto 100C , water Thus, using 8890cal energy we can 12.34 g of ice at 0Cto 100C , water

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