The equilibrium constatnt Kc for the reaction A (g)+B(g) C (g) is 0.75 at 150 de

Question

The equilibrium constatnt Kc for the reaction A (g)+B(g) C (g) is 0.75 at 150 degree C. If 0.800 mol of Ais added to 0.600 mol of B in a 1.00 L container at 150 degree C,what will be the equilibrium concentration of C. a. 0.19M b. 0.36M c. 0.41M d.0.61M Please show work. Thanks The equilibrium constatnt Kc for the reaction A (g)+B(g) C (g) is 0.75 at 150 degree C. If 0.800 mol of Ais added to 0.600 mol of B in a 1.00 L container at 150 degree C,what will be the equilibrium concentration of C. a. 0.19M b. 0.36M c. 0.41M d.0.61M Please show work. Thanks

Explanation / Answer

                                                                   A (g)   +    B (g)    C(g)                                                        I(M)  0.8           0.6            0                                                       C(M)   -x               -x          +x                                                       E(M)   0.8 - x       0.6 -x       +x                                                                             K = (x) / ( 0.8 -x )(0.6 - x )                                                                   x - 0.75 ( 0.8- x )(0.6- x ) = 0 On solving the above equation we get x = 0.188 M                                                             =[ C] So it could be rounded of f to get 0.19 M . Option ais the answer.

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